## What is the acceleration of two falling skydivers mass 132

**(a) What is the acceleration of two falling sky divers (total mass = 132 kg including parachute) when the upward force of air resistance is equal to one-fourth of their weight? (b) After opening the parachute, the divers descend leisurely to the ground at constant speed. What now is the force of air resistance on the sky divers and their parachute?**

**See Fig. 4–44.**

The magnitude and direction of the acceleration of the elevator is in the downward direction.

### Step by Step Solution

TABLE OF CONTENTS

## Step 1. Determine the forces acting on skydivers

**In this case, only two forces will be acting on the skydivers; weight (W) and the normal force (N). Consider the upward direction to be positive and apply Newton’s second law to calculate the skydivers’ acceleration.**

The total mass of the skydivers is .

The normal force is .

The free body diagram of the skydivers is as follows:

The relation to calculate the vertical forces is given by:

Here, a is the acceleration of the skydivers, W is the weight, and N is the normal force.

## Step 2. Determine the acceleration of the skydivers

On plugging the values in the above relation, you get:

Here, g is the gravitational acceleration.

Thus, is the acceleration of the skydivers. The negative sign indicates that the direction of acceleration is downward.

## Step 3. Determine the force of the air resistance

When the skydivers are descending at a constant speed, the total force on them is zero.

The relation to calculate the force of the air resistance is given by:

On plugging the values in the above relation, you get:

Thus, is the force of the air resistance.

## Most popular questions for Physics Textbooks

**Sketch the free-body diagram of a baseball (a) at the moment it is hit by the bat, and again (b) after it has left the bat and is flying toward the outfield. Ignore air resistance.**

**Suppose the pulley in Fig. 4–55 is suspended by a cord C. Determine the tension in this cord after the masses are released and before one hits the ground. Ignore the masses of the pulley and cords.**

**FIGURE 4-55 Problem 35**

**Police investigators, examining the scene of an accident involving two cars, measure 72 m long skid marks on one of the cars, which nearly came to a stop before colliding. The coefficient of kinetic friction between rubber and the pavement is about 0.80. Estimate the initial speed of that car, assuming a level road.**

**A heavy crate rests on the bed of a flatbed truck. When the truck accelerates, the crate stays fixed on the truck, so it, too, accelerates. What force causes the crate to accelerate?**

**A 1280 kg car pulls a 350-kg trailer. The car exerts a horizontal force of** **against the ground in order to accelerate. What force does the car exert on the trailer? Assume an effective friction coefficient of 0.15 for the trailer.**

## What is the acceleration of two falling skydivers mass 132

**(a) What is the acceleration of two falling sky divers (total mass = 132 kg including parachute) when the upward force of air resistance is equal to one-fourth of their weight? (b) After opening the parachute, the divers descend leisurely to the ground at constant speed. What now is the force of air resistance on the sky divers and their parachute?**

**See Fig. 4–44.**

The magnitude and direction of the acceleration of the elevator is in the downward direction.

### Step by Step Solution

TABLE OF CONTENTS

## Step 1. Determine the forces acting on skydivers

**In this case, only two forces will be acting on the skydivers; weight (W) and the normal force (N). Consider the upward direction to be positive and apply Newton’s second law to calculate the skydivers’ acceleration.**

The total mass of the skydivers is .

The normal force is .

The free body diagram of the skydivers is as follows:

The relation to calculate the vertical forces is given by:

Here, a is the acceleration of the skydivers, W is the weight, and N is the normal force.

## Step 2. Determine the acceleration of the skydivers

On plugging the values in the above relation, you get:

Here, g is the gravitational acceleration.

Thus, is the acceleration of the skydivers. The negative sign indicates that the direction of acceleration is downward.

## Step 3. Determine the force of the air resistance

When the skydivers are descending at a constant speed, the total force on them is zero.

The relation to calculate the force of the air resistance is given by:

On plugging the values in the above relation, you get:

Thus, is the force of the air resistance.

## Most popular questions for Physics Textbooks

**Sketch the free-body diagram of a baseball (a) at the moment it is hit by the bat, and again (b) after it has left the bat and is flying toward the outfield. Ignore air resistance.**

**Suppose the pulley in Fig. 4–55 is suspended by a cord C. Determine the tension in this cord after the masses are released and before one hits the ground. Ignore the masses of the pulley and cords.**

**FIGURE 4-55 Problem 35**

**Police investigators, examining the scene of an accident involving two cars, measure 72 m long skid marks on one of the cars, which nearly came to a stop before colliding. The coefficient of kinetic friction between rubber and the pavement is about 0.80. Estimate the initial speed of that car, assuming a level road.**

**A heavy crate rests on the bed of a flatbed truck. When the truck accelerates, the crate stays fixed on the truck, so it, too, accelerates. What force causes the crate to accelerate?**

**A 1280 kg car pulls a 350-kg trailer. The car exerts a horizontal force of** **against the ground in order to accelerate. What force does the car exert on the trailer? Assume an effective friction coefficient of 0.15 for the trailer.**

## What is the acceleration of two falling skydivers mass 132

**(a) What is the acceleration of two falling sky divers (total mass = 132 kg including parachute) when the upward force of air resistance is equal to one-fourth of their weight? (b) After opening the parachute, the divers descend leisurely to the ground at constant speed. What now is the force of air resistance on the sky divers and their parachute?**

**See Fig. 4–44.**

The magnitude and direction of the acceleration of the elevator is in the downward direction.

### Step by Step Solution

TABLE OF CONTENTS

## Step 1. Determine the forces acting on skydivers

**In this case, only two forces will be acting on the skydivers; weight (W) and the normal force (N). Consider the upward direction to be positive and apply Newton’s second law to calculate the skydivers’ acceleration.**

The total mass of the skydivers is .

The normal force is .

The free body diagram of the skydivers is as follows:

The relation to calculate the vertical forces is given by:

Here, a is the acceleration of the skydivers, W is the weight, and N is the normal force.

## Step 2. Determine the acceleration of the skydivers

On plugging the values in the above relation, you get:

Here, g is the gravitational acceleration.

Thus, is the acceleration of the skydivers. The negative sign indicates that the direction of acceleration is downward.

## Step 3. Determine the force of the air resistance

When the skydivers are descending at a constant speed, the total force on them is zero.

The relation to calculate the force of the air resistance is given by:

On plugging the values in the above relation, you get:

Thus, is the force of the air resistance.

## Most popular questions for Physics Textbooks

**Sketch the free-body diagram of a baseball (a) at the moment it is hit by the bat, and again (b) after it has left the bat and is flying toward the outfield. Ignore air resistance.**

**Suppose the pulley in Fig. 4–55 is suspended by a cord C. Determine the tension in this cord after the masses are released and before one hits the ground. Ignore the masses of the pulley and cords.**

**FIGURE 4-55 Problem 35**

**Police investigators, examining the scene of an accident involving two cars, measure 72 m long skid marks on one of the cars, which nearly came to a stop before colliding. The coefficient of kinetic friction between rubber and the pavement is about 0.80. Estimate the initial speed of that car, assuming a level road.**

**A heavy crate rests on the bed of a flatbed truck. When the truck accelerates, the crate stays fixed on the truck, so it, too, accelerates. What force causes the crate to accelerate?**

**A 1280 kg car pulls a 350-kg trailer. The car exerts a horizontal force of** **against the ground in order to accelerate. What force does the car exert on the trailer? Assume an effective friction coefficient of 0.15 for the trailer.**

Source https://www.studysmarter.us/textbooks/physics/physics-principles-with-applications-7th/dynamics-newtons-laws-of-motion/q17-a-what-is-the-acceleration-of-two-falling-sky-divers-tot/

Source https://www.studysmarter.us/textbooks/physics/physics-principles-with-applications-7th/dynamics-newtons-laws-of-motion/q17-a-what-is-the-acceleration-of-two-falling-sky-divers-tot/

Source https://www.studysmarter.us/textbooks/physics/physics-principles-with-applications-7th/dynamics-newtons-laws-of-motion/q17-a-what-is-the-acceleration-of-two-falling-sky-divers-tot/